From 320 mg of o2 6.023

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Webso as we know that 32g of o2=1 mol =6.023*10^23 therefore. 320mg=0.32g=0.01mol=6.023*10^21 from this ,6.023*10^20 moles are removed =0.001 … WebFrom 320 mg of O2 6023 × 1020 molecules are removed the no of moles remained are 9 × 10−3 moles 9 ×10−2moles Zero 3 × 10−3 No of moles = WtMWt or No of Grade From …

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WebThe number of moles of a given element can be calculated by using the equation: Hence, the number of moles of oxygen in 320 gm is N o. ofmoles = givenmass molarmass = … WebJan 30, 2024 · 0.152mol Na(6.02214179 × 1023 atoms Na 1 molNa) = 9.15 × 1022 atoms of Na In this example, multiply the grams of Na by the conversion factor 1 mol Na/ 22.98 g Na, with 22.98g being the molar mass of one mole of Na, which then allows cancelation of grams, leaving moles of Na. bush hat dont starve together

Which has greater mass, 2 grams of hydrogen or 6.023 into 10 to …

WebAug 18, 2013 · 32 g of O 2 =1 mol = 6.023x10 23 Therefore, 320mg = 0.32g = 0.01 mol = 6.023x10 21 From this, 6.023x10 20 moles are removed = 0.001 moles Therefore remaining moles are 0.01-0.001 = 0.009 moles remain This conversation is already closed by Expert Was this answer helpful? 8 View Full Answer WebSo 30.0 grams of oxygen will contain 30.0/32.0 = 0.9375 moles of O2 molecules. In the same way that 1 dozen means 12, 1 mole means 6.022 x 10^23. Therefore, 0.9375 … WebAnswer: Molar mass of oxygen = 32 g/mol. Mass of 6.022 × 10^23 molecules of oxygen = 32 g. So, mass of 6.023 × 10^21 molecules of oxygen = {(6.023 × … bush hat army

121. From 320 mg. of 0,, 6.023 1020 molecules - Brainly

From 320mg of O2 6.023×10^20 molecules are removed then

Web320 mg (or 0.320 g) of oxygen corresponds to 0.01 mole or 6.023×10 21 molecules. Now, 6.023×10 20 molecules are removed. The number of molecules remaining is ( 6.023×10 … WebNov 5, 2024 · Calculate the number of moles in (a) 3.011 × 10^23 atoms of C (b) 32 g of oxygen gas asked Oct 26, 2024 in Chemistry by Saadhvi ( 54.7k points) atoms and … handheld tanita biaWebMolar mass of oxygen = 32 g/mol. Mass of 6.022 × 10^23 molecules of oxygen = 32 g. So, mass of 6.023 × 10^21 molecules of oxygen = { (6.023 × 10^21)/ (6.022×10^23)} × 32 g = 1 × (10^-2 × 32) g = 0.32 g. Therefore, 2 g hydrogen has greater mass. Hope this helps. 2.5K views View upvotes 6 Quora User handheld tactical nuke

"Webchemistry From 320 mgof O2 ,6.023×1020molecules are removed, the no. of moles remained are: A 9×10−3moles B 9×10−2moles C zero D 3×10−3moles Answer Correct … " - From 320 mg of o2 6.023

From 320 mg of o2 6.023

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WebAug 18, 2013 · 32 g of O 2 =1 mol = 6.023x10 23 Therefore, 320mg = 0.32g = 0.01 mol = 6.023x10 21 From this, 6.023x10 20 moles are removed = 0.001 moles Therefore … WebFeb 26, 2024 · Answer: 9.52x10²⁰ sodium ions Explanation: First, we need to convert the mass in moles (n) n = mass/molar mass The moalr mass is given in g/mol, so let's transform the mass in gram: 1 g ------------ 1000 mg x g------------- 99.6 mg By a direct simple three rule: 1000x = 99.6 x = 0.0996 g n = 0.0996/126.05 n = 7.90x10⁻⁴ mol of Na₂SO₃

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WebA mole is like a dozen. It is a name for a specific number of things. There are 12 things in a dozen, and 602 hexillion things in a mole. We'll talk about wh... WebFrom 320 mg. of 0,, 6.023 x 1020 molecules are removed, the no. of moles remained are 1) 9 x 10-3 moles 2) 9 x 10-2 moles 3) Zero 10 4 ) 3 x 10-3 moles lenih Solution Verified by …

WebMar 30, 2024 · Atoms that are neutral or ionized make up every solid, liquid, gas, and plasma. Atoms are incredibly small, measuring about 100 picometers in diameter. … WebAnswer is (a) 16/ 6.023 × 10 23 g Explanation: Mass of one atom of oxygen = Atomic mass/NA = 16/ 6.023 × 10 23 g Note: NA = 6.023×10 23 9. 3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are (a) 6.68 × 1023 (b) 6.09 × 1022 (c) 6.022 × 1023 (d) 6.022 × 1021 Soln: Answer is (a) 6.68 × 10 23

WebJul 22, 2024 · From 320 mg. of 0,, 6.023 1020 molecules are removed, the no. of moles remained are 1) 9 x 10 moles 2)9 x 102 moles 3) Zero 4)3 x 103 moles Advertisement Answer 1 person found it helpful cdtsubhamkhatua Answer: 3 zero Explanation: this may be correct Find Chemistry textbook solutions? Preeti Gupta - All In One Chemistry 11 3080 … WebApr 17, 2024 · Answer: 32g of O2=1mol=6.023×1023 molecules ∴320mg=0.32g=0.01mol=6.023×1021 From this 6.023×1020 moles are removed= 0.001 …

WebFrom 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the no. of moles remained are A. `9 xx 10^(-3)` moles B. `9 xx 10^(-2)` moles C. Zero D. `3 xx 10^(-3)` moles

Web(c) 320 mg of gaseous SO2 (d) All the above 27. 4.4 g of an unknown gas occupies 2.24 liters of volume at STP. The gas may be (a) carbon dioxide (b) carbon monoxide (c) oxygen (d) Sulphur dioxide P a g e 3 f Institute of Language & Sciences CHEMISTRY ENTRY-2024 Practice Sheet – 1.2 28. Which of the following has the smallest number of molecules? handheld tamper poolWebAdditionally, the by-products of oxygen and hydrogen evolution reactions are H1 and OH2 ions, which facilitate the local pH changes of the electrolyte in the nearby regions, affecting the stability of the dissolved metal ions and failure modes such as ECM. (2.12) 2H2 O-O2ðgÞ 1 4H1 1 4e2 E0 5 0:401V at pH14 Therefore when the electrolytic cell ... handheld tablet barcode scannerWebEvery mole of SO2 requires one mole of S and one mole of O2. 6.023 x 10^24 molecules is 10 moles. The atomic mass of S is 32 g/mol and the molecular weight of O2 is also 32 g/mole. So, 10 moles of each will be 320 g. 4 More answers below Barry Austern handheld tamping rammer factoryWeb3 vols. of oxygen require KClO 3 = 2 vols. So, 1 vol. of oxygen will require KClO 3 = So, 6.72 litres of oxygen will require KClO 3 = 22.4 litres of KClO 3 has mass = 122.5 g So, 4.48 litres of KClO 3 will have mass = ii. 22.4 litres of oxygen = 1 mole So, 6.72 litres of oxygen = No. of molecules present in 1 mole of O 2 = 6.023 × 10 23 bush hat manufacturers south africaWeb$$320$$ mg (or $$0.320$$ g) of oxygen corresponds to $$0.01$$ mole or $$6.023 \times 10^{21}$$ molecules. From this, $$6.023 \times 10^{20}$$ molecules are removed. The … bush hat australiaWebStudy with Quizlet and memorize flashcards containing terms like How many grams of N2O4 correspond to 5.22 x 10^22 molecules of N2O4? Avogadro's number is 6.022 x 10^23, correctly reflects avogadros number, correct steps to … handheld tally counterWebOxygen is a diatomic molecule= O 2 = (16x2) = 32 g in one mole. As we know, 32 g of O 2 =1 mol = 6.023x10 23. Therefore, 320mg = 0.32g = 0.01 mol = 6.023x10 21. From this, … bush hat for women